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Given f(x)=x2+3x-5 on [-1,3]
show f(x)= 10 without solving for x

  • Calculus -

    f(x) is not 10
    Not sure what you're after here. Do you mean that there exists a c such that -1 <= c <= 3 where f(c) = 10?

    f(-1) = 3
    f(3) = 13

    Since f(x) is continuous, there is such a c.

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