Calculus
posted by Brandon .
integral of cscx^(2/3)(cot^3)x
i know that cot^2x is csc^2(x)1, but i just don't understand how to solve the cscx^(2/3), any help? i also know that its trig integrals/substitution...

let u = csc(x)
du = csc(x) cot(x)
cot^2 = csc^2  1
and you have
csc^(2/3) (csc^21)cot(x)
= csc^(5/3)(csc*cot)  csc^(1/3)(csc*cot)
= [u^5/3 + u^(1/3)] du
all downhill from there
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