Calculus
posted by HELP ME PLEASE! .
From each corner of a square piece of cardboard, remove a square of sides 3 inch. Turn up the edges to form an open box. If the box is to hold 300 inch cubed, what are the dimensions of the original piece of cardboard?

v = 3(x6)^2
when v=300, we have (x6)^2 = 100, so x = 16.
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