A 5630 kg open railroad car coasts along with a constant speed of 8.64 m/s on a level track. Snow begins to fall vertically and fills the car at a rate of 3.50 kg per minute. Ignoring friction with the tracks, what is the speed of the car after 94.8 min?
Lateral momentum remains the same if friction can be ignored.
331.8 kg of snow is added in 94.8 minutes.
5630*8.64 = (5630 + 331.8)*Vfinal
Solve for Vfinal.
I can't imagine frictionless motion on a railroad track that is piled high with snow. In the real world, you can't blindly make wrong assumptions just to make the problem solving easier.
A man with a mass of 64.1 kg stands up in a 61-kg canoe of length 4.00 m floating on water. He walks from a point 0.75 m from the back of the canoe to a point 0.75 m from the front of the canoe. Assume negligible friction between the canoe and the water. How far does the canoe move?
To find the speed of the car after 94.8 minutes, we need to consider the changes in momentum caused by the snow filling the car.
First, let's calculate the initial momentum of the car:
Initial momentum (before snowfall) = mass × velocity
= 5630 kg × 8.64 m/s
Since there is no friction with the tracks, the momentum of the car will remain constant throughout the process.
Next, let's calculate the momentum of the snow that enters the car:
Momentum (snow) = mass × velocity
= (3.50 kg/min) × (94.8 min)
Now, we can calculate the final momentum of the car after the snowfall:
Final momentum (after snowfall) = Initial momentum + Momentum (snow)
Finally, we can find the final velocity of the car after the snowfall by dividing the final momentum by the mass of the car:
Final velocity = Final momentum / mass
Following these steps, you can calculate the final velocity of the car.