Average Value  Calculus
posted by KAITLIN .
What is the average value of y for the part of the curve y = 4x − x^3 that is in the first quadrant?

since there are roots at 0 and 2, integrate from 0 to 2 and divide by the interval length (2).
(2x^2  1/4 x^4)[0,2]/2 = 4/2 = 2
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