posted by .

A spring with k = 54 N/cm is initially stretched 1 cm from its equilibrium length.

(a) How much more energy is needed to further stretch the spring to 2 cm beyond its equilibrium length?
(b) From this new position, how much energy is needed to compress the spring to 2 cm shorter than its equilibrium position?

  • Physics -

    PE1 =k•x1²/2
    PE2 = k•x2²/2
    W = ΔPE =PE2 –PE1 =k(x2² - x1²)/2 = ….
    where k =54 N/m, x1 =0.01 m,
    x2 =0.01+0.02 = 0.03 m.

    this compression will be done by the work of elastic force of the spring. When we release the spring which is stretched by 0.03 m, the released energy is k•(0.003)²/2 which is large than k•(0.02)²/2.

  • Physics -

    I'm still a little confused. When I use the equation:
    W = k(x2^2 - x1^2)/2, I get 0.0216 J. This doesn't seem correct.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. physics

    I have a question involving the spring costant: A 2-kg block is attached to a horizontal ideal spring with a spring constant of 200N/m. When the spring has its equilibrium length the block is given a speed of 5 m/s. What is the maximum …
  2. physics

    a spring with spring constant k= 100N/m is at its equilibrium length a) how much elastic potential energy is stored in the spring?
  3. Physics

    A spring with spring constant k=100 (N/m) is at its equilibrium length. a) How much elastic potential energy is stored in the spring?
  4. Physics

    The length of a spring increases by 7.2 cm from its relaxed length when a mass of 1.4 kg is hanging in equilibrium from the spring. (a) What is the spring constant?
  5. physics

    A spring exerts a 17 N force after being stretched by 3.0 cm from its equilibrium length. By how much will the spring force increase if the spring is stretched from 5.0 cm away from equilibrium to 6.0 rm cm from equilibrium?
  6. physics

    Imagine a spring floating in space. This spring has a very small length when it is unstretched. The spring constant for this spring is 4.2 N/m. Now place 2.6 μC charges on each end of the spring, and allow it to stretch until …
  7. Calculus

    Suppose that 5 J of work is needed to stretch a spring from its natural length of 28 cm to a length of 36 cm. (a) How much work is needed to stretch the spring from 32 cm to 34 cm?
  8. Math

    Hooke's Law states that the distance a spring will stretch beyond its natural length varies directly with the force applied to the spring. A force of 12 pounds is needed to stretch a certain spring 9 inches beyond its natural length. …
  9. Spring Physics

    A block of mass 3 kg is hung from a spring, causing it to stretch 9 cm at equilibrium. The 3 kg block is then replaced by a 4 kg block, and the new block is released from the position shown below, at which point the spring is unstretched.WHAT …
  10. Calculus 2

    Suppose that a spring has a natural length of 25 ​cm, and that 8 J of work is needed to stretch from a length of 50 cm to 80 cm. How far beyond its natural length will a force of 32 N keep the spring​ stretched?

More Similar Questions