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Calculate the moment of Inertia for a ring with a mass 0.715 kg, an inner radius of 10.7 cm and an outer radius of 12.7 cm.

  • physics -

    m•(R² + r ²)/2

  • physics -

    I=0.5*M*(R^2+r^2)

    I=0.5*0.715kg*[(12.7cm)^2+(10.7cm)^2]

    I=98.6 kg*cm^2

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