# Chemistry

posted by .

100.0 mL Vinegar (d=1.06g/mL) contains 4% acetic acid.
a. How many moles of acid are in 100 mL of vinegar?
b. How many mL of 0.11 M NaOH are required to neutralize the vinegar?

• Chemistry -

Is that 4% w/w. If so, that means 4g acetic acid/100 g soln.
4 g acetic acid = 4/molar mass = approximately 0.7 mols (but you need to do that exactly).
Convert 100 g soln to L, then M vinegar = mols/L.

For part b, mL NaOH x M NaOH = mL vinegar x ZM vinegar.

• Chemistry -

That is super helpful, thanks. I missed a two days of class when we learned acids and bases, so I was a bit stuck.

## Similar Questions

1. ### Gen. Chemistry lab

Trying to find mass percent of acetic acid in 25 drops of .683M NaOH solution are required to neutralize 10 drops of cleaning vinegar. Assume that the density of the cleaning vinegar is the same as the density of regular vinegar which …
2. ### Chemistry

Ok, in this question, the drops is throwing me off totally, can someone help! A nationally known company markets a product called "cleaning vinegar" that is not designed for human consumption. What is the mass percent of acetic acid …
3. ### chem.

A 10.0 mL of vinegar, an aqueous solution of acetic acid (HC2H3O2), is titrated with .5062M NaOH, and 16.58mL is required to reach the equivalence point. A. What is the molarity of the acetic acid?
4. ### chem-acid-base titrations

Acetic acid (HC2H3O2) is an important component of vinegar. A 10.00mL sample of vinegar is titrated with .5052 M NaOH, and 16.88 mL are required to neutralize the acetic acid that is present. a.write a balanced equation for this neutralization …
5. ### Chemistry

Greetings: I was wondering how to calculate the weight/volume % of vinegar using the formula ---------------w/v Per Cent = g/100 mL or grams per deciliter: WHAT WEIGHT DO I USE NaOH, Acetic ACID?
6. ### Chemistry

Hi, could someone help me with these calculations for my lab; Given: Volume of vinegar analyzed:5 mL Con'c of NaOH: 0.09890M Avg. V of NaOH from titration:43.75 mL Moles of NaOH required to reach the equivalence point: ?
7. ### Chemistry

Thanks for your help; I am still have a few problems, could you check my work: Given: Volume of vinegar analyzed-5mL Con'c of NaOH-0.09890M Avg. Volume of NaOH from titration-43.75mL Density CH3COOH: 1.049g/mL Calculations: 1.Moles …
8. ### chemistry

4. Vinegar is a dilute solution of acetic acid. What is the concentration of acetic acid in the vinegar if 26.5 mL of NaOH at 0.250 M are required to neutralize 10.0 mL of vinegar?
9. ### Chemistry

Vinegar is a dilute solution of acetic acid. What is the concentration of acetic acid in the vinegar if 26.5 mL of NaOH at 0.250 M are required to neutralize 10.0 mL of vinegar?
10. ### Chemistry

Vinegar is a solution of acetic acid, CH3COOH, dissolved in water. A 4.69 g sample of vinegar was neutralized by 32.97 mL of 0.100 M NaOH. What is the percent by weight of acetic acid in the vinegar?

More Similar Questions