HOW MANY GRAMS OF LITHIUM DO YOU NEED TO REACT WITH 2.5 X 10^24 FLUORINE MOLECULES TO PRODUCE LITHIUM FLUORIDE?
To determine the number of grams of lithium needed to react with a given number of fluorine molecules and produce lithium fluoride, we need to consider the balanced chemical equation for the reaction.
The balanced chemical equation for the reaction between lithium and fluorine to produce lithium fluoride is:
2 Li + F2 -> 2 LiF
From the balanced equation, we can see that 2 moles of lithium react with 1 mole of fluorine to produce 2 moles of lithium fluoride.
To find the number of moles of fluorine molecules described by 2.5 x 10^24, we need to convert this quantity to moles.
1 mole of any substance contains 6.022 x 10^23 particles (Avogadro's number). Therefore, to convert the number of fluorine molecules to moles, we divide the given quantity (2.5 x 10^24) by Avogadro's number:
Number of moles of fluorine = (2.5 x 10^24) / (6.022 x 10^23)
Once we have the number of moles of fluorine, we can determine the number of moles of lithium needed to react by using the stoichiometric coefficients from the balanced equation. We can see that 2 moles of lithium react with 1 mole of fluorine.
Number of moles of lithium = (Number of moles of fluorine) / 2
Finally, to find the mass of lithium needed, we can multiply the number of moles of lithium by the molar mass of lithium (6.941 g/mol):
Mass of lithium = (Number of moles of lithium) x (Molar mass of lithium)
Now, you can plug in the values and calculate:
Number of moles of fluorine = (2.5 x 10^24) / (6.022 x 10^23)
Number of moles of lithium = (Number of moles of fluorine) / 2
Mass of lithium = (Number of moles of lithium) x (Molar mass of lithium)
Note: Ensure that your units are consistent throughout the calculations.
I hope this explanation helps you understand the process of calculating the grams of lithium required to react with a certain number of fluorine molecules.