posted by skyler
If an excess of nitrogen gas reacts with 25.0 L of hydrogen gas, according to the reaction below, how many L of ammonia will be produced?
N2(g) + 3H2(g) ---> 2NH3(g)
When everything is in the gaseous state, one may use a short cut; i.e., it isn't necessary to convert to mols of what you have, then to mols of what you want, and back to moles of what you want. Go directly from L of what you have to L of what you want.
25.0L H2 gas x (2 moles NH3/3 mole H2) = ? L NH3.
What is the oxidizing agent during discharge