physics

posted by .

a train starts from rest and accelerates uniformly at 100m/min^2 for 10 min.then it maintains a constant velocity for remaining 20 min.brakes are applied and train uniformly retards and comes to rest in next 5 min.
a)the maximum velocity reached
b)the retardation in last 5 min
c)total distance traveled
d)the average velocity of the train.

  • physics -

    a. V = Vo + at
    V = 0 + 100m/min^2 * 10min = 1000 m/min


    b. a=(V-Vo)/t=(0-1000) / 5=-200m/min^2

    c. d1 = 0.5a*t^2 = 50*10^2 = 5000 m.
    d2 = 1000m/min * 20min = 20,000 m.
    d3 = Vo*t + 0.5a*t^2
    d3 = 1000*5 + (-100)*5^2 = 2500 m.

    d1+d2+d3 = 5000 + 20000 + 2500=27,500 m
    = Tot. dist. traveled.

    d. T = t1 + t2 + t3 = 10+20+5 = 35 Min.
    Va=(d1+d2+d3)/T=27,500m/35min=786 m/min
    = Average velocity.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Physics

    A train travels between stations 1 and 2. The engineer of the train is instructed to start from rest at station 1 and accelerate uniformly between points A and B, then coast with a uniform velocity between points B and C, and finally …
  2. physics

    A train moving at a constant speed of 68.0 km/h moves east for 33.0 min, then in a direction 40.0° east of due north for 30.0 min, and then west for 59.0 min. What is the average velocity of the train during this run?
  3. Physics

    A train moving at a constant speed of 68.0 km/h moves east for 36.0 min, then in a direction 48.0° east of due north for 30.0 min, and then west for 45.0 min. What is the average velocity of the train during this run?
  4. Physics

    A train travels between stations 1 and 2. The engineer of the train is instructed to start from rest at station 1 and accelerate uniformly between points A and B, then coast with a uniform velocity between points B and C, and finally …
  5. physics

    a train starts from rest and accelerates uniformly to achieve a velocity of 20m/sec in 10 sec.then train maintains this speed for next 200 sec.the breaks are then applied and train comes to rest in next 50 sec.calculate a)acceleration …
  6. physics

    a train starts from rest and accelerates uniformly at 100m/min^2 for 10 min.then it maintains a constant velocity for remaining 20 min.brakes are applied and train uniformly retards and comes to rest in next 5 min. a)the maximum velocity …
  7. physics

    a train starts from rest and accelerates uniformly to achieve a velocity of 20m/sec in 10 sec.then train maintains this speed for next 200 sec.the breaks are then applied and train comes to rest in next 50 sec.calculate a)acceleration …
  8. physics

    a train starts from rest and accelerates uniformly at 100m/min^2 for 10 min.then it maintains a constant velocity for remaining 20 min.brakes are applied and train uniformly retards and comes to rest in next 5 min. a)the maximum velocity …
  9. physics

    a train starts from rest and accelerates uniformly to achieve a velocity of 20m/sec in 10 sec.then train maintains this speed for next 200 sec.the breaks are then applied and train comes to rest in next 50 sec.calculate a)acceleration …
  10. Physics

    A train moving at a constant speed of 61.0 km/h moves east for 35.0 min, then in a direction 50.0° east of due north for 10.0 min, and then west for 49.0 min. What is the average velocity of the train during this run?

More Similar Questions