Algebra

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How long does it take a care traveling 100 mph to catch up to a car traveling 80 mph

  • Algebra -

    Depends how far back the faster car was.
    Not enough data.

  • Algebra -

    Leaves 2 minutes after the car at 80 mph passes it

  • Algebra -

    The car traveling 100 mph states from a complete stop

  • Algebra -

    Key point:
    When the faster catches the slower , they both went the same distance
    let that distance be x miles
    time for faster car = x/100
    time for slower car = x/80
    x/80 - x/100 = 2/60
    x/400 = 1/30
    30x = 400
    x = 40/3 miles

    so time for faster car to go the 40/3 miles to catch the slower car
    = (40/3) / 100 = .13333.. hr
    = 8 minutes


    check:
    time for slower car
    = (40/3) / 80 = .166666 hrs
    = 10 minutes, for a difference of 2 minutes

  • Algebra -

    Thanks!

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