posted by Hannah .
1) A cave explorer drops a stone from rest into a hole. The speed of sound is 343 m/s in air, and the sound of the stone striking the bottom is heard 1.33 s after the stone is dropped. How deep is the hole?
I did 343 / 1.33. Is this correct?
No. Dividing a speed by a time gives you an acceleration rate. You have to write an equation for the time it takes to hear the sound. That time consists of two terms: stone drop time and sound travel time.
See "related questions" below
This solution to a similar problem may help:
So I would set my problem up as
(13.3 - X/343)^2 = x/1.76
The only thig I am not sure of is how to solve for the x.