posted by srikala .
a bullet fired into a fixed target loses half of its velocity in penetrating 15cm.how much further will it penetrate before coming to rest?
3/4 of the initial kinetic energy is used up going the first 15 cm. There is enoough left to penetrate 1/3 as far (5 cm). This assumes that the force resisting penetration is constant.
i think it should be 1/3rd if 15 i.e. cm but not sure...
i also don't know correctly but if anyone knows please let me know....
5 cm..Use v^2-u^2=2as...Hope u will get the answer...or do it by using the method of
conservation of energy