posted by Hannah .
1) A force vector has a magnitude of 579 newtons and points at an angle 43o of below the positive x axis.
Find the x scalar component and the y scalar component of the vector?
For the x component I did 579cos(43) = 423.45 N. Is this correct?
For the y component I did 579sin(43) but this was incorrect. I am not sure what to do.
The angle is -43°, not 43°
The vector points below the x-axis, so sin is negative.