Alg 2
posted by Griselda .
classify the conic section for (x+3)^2/16  (y5)^2/64 = 1

Hyperbola
Equation of hyperbola :
( x  h ) ^ 2 / a ^ 2  ( y  k ) ^ 2 / b ^ 2 = 1
In this case :
( x + 3 ) ^ 2 / 16  ( y  5 ) ^ 2/ 64 = 1
[ x  (  3 ) ] ^ 2 / 4 ^ 2  ( y  5 ) ^ 2 / 8 ^ 2 = 1
h =  3
k = 5
a = 4
b = 8