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The PH of a 1.3M HF solution is 3.18. What % of the acid ionized?

  • Chemistry -

    pH = -log(H^+)
    3.18 = -log(H^+)
    (H^+) = 6.6E-4 but you should confirm that.

    ...........HF ==> H^+ + F^-
    %ionization = (6.6E-4/1.3)*100 = ?

  • Chemistry -

    thank you!!

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