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the diagonals of a rhombus are 24 meter and 18 meter find the area,length of a side and perimeter?

  • maths -

    recall these properties:
    -all sides of rhombus are equal.
    -the diagonals of rhombus are perpendicular (forms four 90 degree angles)
    -area of rhombus, if diagonals are given, can be calculated by
    A = d1 * d2 /2
    where d1 & d2 are the diagonal lengths
    -side of a rhombus, if diagonals are given, can be calculated by
    s = sqrt(d1^2 + d2^2)
    *note that this is just pythagorean theorem

    applying these,
    A = 24*18/2
    A = 216 m^2

    s = sqrt(24^2 + 18^2)
    s = sqrt(900)
    s = 30 m

    P = 4*s
    P = 4*30
    P = 120 m

    hope this helps~ :)

  • maths -

    A=D1*D2 LIKE D=24 AND 18. SO 24*18=432. THEREFORE AREA=432 . AND SIDE= SQRT D1*2+D2*2 . SO GIVEN D1 AND D2 =24 AND 18 =SQRT 24^2 +18^2= 576+324 =900 THEREFORE SIDE= sqrt900=30.

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