Calculus I
posted by Marissa .
Find the derivative of
y=ln((1+e^x)/(1e^x))
I know that the derivative of y=ln(1+e^x) would be (e^x)/(1+e^x), but I'm not sure what to do with the 1e^x on the bottom here. Can someone help please? Thanks!

In google type:
wolfram alpha
When you see lis of results click on:
Wolfram Alpha:Computational Knowledge Engine
When page be open in rectangle type:
derivartive ln((1+e^x)/(1e^x))
and click option =
After few secons you will see result.
Then clic option Show steps 
first of all recall that
ln (A/B) = ln A  ln B
so
y = ln((1+e^x)/(1e^x) )
= ln (1+e^x)  ln (1e^x)
dy/dx = e^x/(1+e^x)  (e^x)/(1  e^x)
simplify as needed 
Okay, thanks guys!
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