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In one room the radiator has a dark color (emissitivity = 0.818). It has a temperature of 64.8 oC. The new owner of the house paints the radiator a lighter color (emissitivity = 0.417). Assuming that it emits the same radiant power as it did before being painted, what is the temperature (in degrees Celsius) of the newly painted radiator?

  • physics -

    The Stefan-Boltzmann equation must use temperature in K.

    T1 = 64.8 C = 338.0 K
    If the radiating area stays the same,
    0.818 T1^4 = 0.417 T2^4, so
    T2 = 1.1835*T1 = 400.0 K = 126.8 C

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