# Physics

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A 5.0 µC point charge is moved within an electric field and has an electric potential energy change of 10.0 J. What is the electric potential difference before and after the charge was moved? Show work. (µC = 1.0 × 10–6

Vq=energy
so delta V must be 10 volts.
What do I do NOW?

• Physics -

You mean V * q = energy
so
V = energy / q

The potential difference * charge = potential energy change of charge

delta V = 10J/(5*10^-6) = 2*10^6 volts

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