Calculus!
posted by kelsey .
Which is the standard form of the equation with p = 26, O=3pi/4 ?
the O before the =3pi has a diagonal slash through it.

You have written two equations that seem to describe two polar coordinates. Is "p" the radisl distance from the origin?
It is not clear what you mean by "standard form"
Respond to this Question
Similar Questions

precalc
Can someone help me find the exact value of 4csc(3pi/4)cot(pi/4)? 
PreCalculuscheck answers
State the period and phase shift of the function y=4tan(1/2x + 3pi/8) a) 2pi, 3pi/4 b) pi, 3pi/8 c) 2pi, 3pi/8 d) pi, 3pi/8 Answer: d 2) What is the equation for the inverse of y=cos x+3: a) y=Arccos(x+3) b) y=Arccos x3 c) y=Arccos … 
Math
Test for symmetry with repsect to Q=pi/2, the polar axis, and the pole. r=16cos 3Q r=16cos(3pi/3 + 3h) = 16(cos3pi/2 3h sin 3pi/2 sin h) cos 3pi/2 = 0 sin 3pi/2 = 1 Not symmetrical My teacher said that this was wrong!Why? 
Math
Test for symmetry with repsect to Q=pi/2, the polar axis, and the pole. r=16cos 3Q r=16cos(3pi/3 + 3h) = 16(cos3pi/2 3h sin 3pi/2 sin h) cos 3pi/2 = 0 sin 3pi/2 = 1 Not symmetrical My teacher said that this was wrong!Why? 
Calculus
Determine whether the curve has a tangent at the indicated point. f(x)= sin x 0<x<3pi/4 cos x 3pi/4<x<2pi at x = 3pi/4 
trig
Solve the equation for cos thetatan theta=0 for greater than or egual to zero but less than 2pi. Write your answer as a multiple of pi, if possible form the following choices: pi , 5pi A.   4___ 4 B. pi 3pi 5pi 7pi  ' … 
Calculus
Which is the standard form of the equation with p = 26, O=3pi/4 ? 
trig
Solve cos x1 = sin^2 x Find all solutions on the interval [0,2pi) a. x=pi, x=pi/2, x= 2pi/3 b. x=3pi/7, x=pi/2, x=2pi/3 c. x=3pi/7, x=3pi/2, x=3pi/2 d. x=pi, x=pi/2, x=3pi/2 
Calculus
If f(x)=sinx and g(x)=cosx, then the set for all x for which f'(x)=g'(x) is: A. Pi/4 + k(pi) B. Pi/2 + k(pi) C. 3pi/4 +k(pi) D. Pi/2 + 2k(pi) E. 3pi/2 + 2k(pi) 
Algebra 2
What values for theta(0 <= theta <= 2pi) satisfy the equation?