Chemistry!!

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Calculate the pH at the equivalence point for the titration of 0.180 M methylamine (CH3NH2) with 0.180 M HCl. The Kb of methylamine is 5.0× 10^–4.

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    At the equivalence point we have the salt, CH3NH3Cl and it will hydrolyze to give you an acidic solution. (salt) at the equivalence point is 0.09M.
    .........CH3NH3^+ + H2O == H3O^+ + CH3NH2
    I.........0.09..............0........0
    C...........-x..............x........x
    E.......0.09-x..............x........x

    Kb = (CH3NH2)(H3O^+)/((CH3NH3^+)
    Substitute and solve for x = (H3O^+) and convert to pH.

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