Chemistry

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A 100 mL container is filled with 0.01 mol of A2B3. At equilibrium, it also contains 0.006 mol of B. Find the value of K.

A2B3(g) --> 2A(g) +3B(g)

  • Chemistry -

    ........A2B3 ==> 2A + 3B
    I......0.01.......0....0
    C.......-x........2x...3x
    E....0.01-x.......2x...3x

    The problem tells us that 3x = 0.006 = mols B; therefore, x = 0.006/3 = 0.002
    Equilibrium mols are as follows:
    A2B3 = 0.01-0.002 = ?
    A = 2*0.002 = ?
    B = 0.006
    These are mols. You must convert to molarity. Do that by M = mols/L. The volume is given as 0.1L. Then substitute concns into the Keq expression and solve for Kc.

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