statistics
posted by john .
Suppose that 98% of your customers in your market have internet access and you select a random sample of 500 customers. What is the standard error of the proportion of customers who don’t have internet access?
I seem to be struggling with no standard deviation listed

Standard deviation = √npq = √(500 * .98 * .02) = ?
(Note: q = 1  p)
I'll let you finish.
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