math
posted by Cj .
Jeff wants to start a lawn maintenance service to earn money for college. He wants to charge $25 for a small lawn and $35 for a large one. It takes him an average of 2 hours to mow and trim a small lawn and 3 hours to do a large one. He wants to make at least $250 a week but can work no more than 20 hours every week.
If x is the number of small lawns and y is the number of large lawns, which ordered pair is a solution to the system of inequalities which describes Jeff's situation?

Don't see any choices, but we do know
2x + 3y <= 20
25x + 35y >= 250
If he does 10 small lawns, that's 20 hrs and $250
He can't do any large lawns, since he can do at most 8 small lawns for $200, and can't make up the difference and stay under 20 hours:
S L Hrs $$$
10 0 20 250
9 0 18 225
8 1 19 235
7 2 20 245
6 2 18 220
. . .
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