posted by sharmila .
an architect wants to draw a rectangle with a diagonal of 13 inches.the length of the rectangle is to be 2 inches more thn twice the width.what dimensions should she make the triangle.
(a)set up an equation:
(b)solve the equation:
(c)write a sentence that answers the quation:
Dia. = 13 In. = Hyp. of rt triangle.
Width=x In.=Ver. side of a rt triangle
Length = 2x+2 In. = Hor. side of rt triangle.
a. (2x+2)^2 + x^2 = 13^2.
b. 4x^2+8x+4 + x^2 = 169
5x^2 + 8x -165 = 0
Use Quadratic Formula:
X = 5 In.
X = -6.6 Not valid.
2x+2 = 2*5 + 2 = 12 In.