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if the [H] of a solution at 25degrees is 1.7*10^-4 mol/L, calculate the [OH] in mol/L, the PH, and the pOH?


    pH = -log(H^+)
    pOH = -log(OH^-)
    pH + pOH = pKw = 14 and
    (H^+)(OH^-) = Kw.
    One or more of the four above will calculate all you ever need to know abouat H^+), (OH^-), pH and pOH.


    THANK YOU :)

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