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Algebra 1

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3x + 4y = -2 and 2x - 3y = 10

  • Algebra 1 -

    many ways to solve this: substitution, graphing, system of equations, etc.

    I prefer system of equations, so here you go!

    2(3x + 4y = -2) 6x + 8y = -4
    3(2x - 3y = 10) -(6x - 9y = 30)subtract
    17y = -34
    y = -2
    plug in -2 for y into one of the equations and solve...

    3x + 4(-2) = -2
    3x=6
    x=2

  • Algebra 1 -

    Are we finding the intersection of these two lines ???
    if so then

    multiply the 1st by 3 ---> 9x + 12y = -6
    multiply the 2nd by 4 ---> 8x - 12y = 40
    add them
    17x = 34
    x = 2
    plug that into the 1st
    3(2) + 4y = -2
    4y = -8
    y = -2

    x = 2, y = -2

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