# Algebra 1

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3x + 4y = -2 and 2x - 3y = 10

• Algebra 1 -

many ways to solve this: substitution, graphing, system of equations, etc.

I prefer system of equations, so here you go!

2(3x + 4y = -2) 6x + 8y = -4
3(2x - 3y = 10) -(6x - 9y = 30)subtract
17y = -34
y = -2
plug in -2 for y into one of the equations and solve...

3x + 4(-2) = -2
3x=6
x=2

• Algebra 1 -

Are we finding the intersection of these two lines ???
if so then

multiply the 1st by 3 ---> 9x + 12y = -6
multiply the 2nd by 4 ---> 8x - 12y = 40
17x = 34
x = 2
plug that into the 1st
3(2) + 4y = -2
4y = -8
y = -2

x = 2, y = -2

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