Consider the following reaction. Assume that there is excess C3H7SH present. If we start with 0.5 moles O2, how many mols of SO2 can form?
C3H7SH + 6O2 ==> 3CO2 + 4H2O + SO2
0.5 mol O2 x (1 mol SO2/6 mol O2) = 0.5 x 1/6 = ?
8x10 -2
To determine the number of moles of SO2 that can form in the reaction, we need to use the balanced equation for the reaction and stoichiometry.
The balanced equation for the reaction is:
2 C3H7SH + 9 O2 → 6 CO2 + 6 H2O + 2 SO2
According to the equation, for every 9 moles of O2 consumed, 2 moles of SO2 will be produced. We are given that there is an excess of C3H7SH, so we can assume that all the O2 will be consumed in the reaction.
To calculate the number of moles of SO2 that can form, we can use the following stoichiometric ratio:
(0.5 moles O2) × (2 moles SO2 / 9 moles O2) = 0.1111 moles SO2
Therefore, 0.1111 moles of SO2 can form in the reaction.