Write an equation in standard form (slope-intecept form) of the line passing through the pair of points (3,4) and (5,8) containing point (5,9) and parallel to the line.
sorry. I think you've garbled the question. As stated, it has no solution. In fact, it doesn't even make sense.
If you're going to post problems, at least copy them correctly.
Can you give to me answer
To find the equation of a line in slope-intercept form (y = mx + b), we need the slope (m) and the y-intercept (b).
Given that the line is parallel to another line passing through the points (3,4) and (5,8), we can start by finding the slope of the original line using the formula:
m = (y2 - y1) / (x2 - x1)
m = (8 - 4) / (5 - 3)
m = 4 / 2
m = 2
Since the line we are looking for is parallel to this line, it will have the same slope. Therefore, the equation of the line we are searching for will have a slope (m) of 2.
Next, we can use the point-slope form of a linear equation to find the equation of the line containing the given point (5,9) with a slope of 2:
y - y1 = m(x - x1)
Substituting the values of the given point and the slope:
y - 9 = 2(x - 5)
Expanding the equation:
y - 9 = 2x - 10
To convert the equation into standard form, we move all terms to one side of the equation:
-2x + y = -1
Thus, the equation in standard form (slope-intercept form) of the line passing through the points (3,4) and (5,8), containing point (5,9), and parallel to the line is -2x +y = -1.