Post a New Question

Physics- Final exam help

posted by .

A proton with kinetic energy 100 keV is moving in a plane perpindicular to a uniform magnetic field of magnitude 2.3 T. Find the radius of its orbit.

Not sure what equation to use or how to solve.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. physics

    An electron of kinetic energy 41 keV moves in a circular orbit perpendicular to a magnetic field of 0.330 T. (a) Compute the radius of the orbit. The answer to this part is 2.07mm. (b) Find the frequency of the motion. I'm not sure …
  2. Physics

    In a certain cyclotron a proton moves in a circle of radius 0.5m. The magnitude of the magnetic field is 1.2T. a) What is the oscillator frequency?
  3. Physics 3

    A 2.3-keV proton is moving horizontally and passes perpendicular to the Earth’s magnetic field at a location where the field magnitude is 52.0 T. i) Determine the magnetic force on the proton?
  4. Physics 3

    A 2.3-keV proton is moving horizontally and passes perpendicular to the Earth’s magnetic field at a location where the field magnitude is 52.0 T. i) Determine the magnetic force on the proton?
  5. Physics pls help

    A proton is moving in a circular orbit of radius 11.8 cm in a uniform magnetic field of magnitude 0.232 T directed perpendicular to the velocity of the proton. Find the orbital speed of the proton. Answer in units of m/s. I came up …
  6. physics

    A proton traveling at 10^4 m/s in the positive x-direction, enters a region where there is uniform electric field of magnitude 10 v/m and a uniform magnetic field of magnitude 10^-2 T. The electric and magnetic fields are parallel …
  7. physics

    A proton traveling at 10^4 m/s in the positive x-direction, enters a region where there is uniform electric field of magnitude 10 v/m and a uniform magnetic field of magnitude 10^-2 T. The electric and magnetic fields are parallel …
  8. physics-Electric & magnetic fields

    A proton traveling at 10^4 m/s in the positive x-direction, enters a region where there is uniform electric field of magnitude 10 v/m and a uniform magnetic field of magnitude 10^-2 T. The electric and magnetic fields are parallel …
  9. physics

    Find the value of the magnetic field necessary to cause a proton moving at a speed of 2.50 ×10^3 m/s to go into a circular orbit of 15.5-cm radius. An electron has an energy of 100 eV as it enters a magnetic field of 3.50 × 10−2 …
  10. Physics- Final exam review

    A proton with kinetic energy 100 keV is moving in a plane perpindicular to a uniform magnetic field of magnitude 2.3 T. Find the radius of its orbit. Not sure what equation to use or how to solve

More Similar Questions

Post a New Question