# Physics- Final exam help

posted by .

A proton with kinetic energy 100 keV is moving in a plane perpindicular to a uniform magnetic field of magnitude 2.3 T. Find the radius of its orbit.

Not sure what equation to use or how to solve.

## Similar Questions

1. ### physics

An electron of kinetic energy 41 keV moves in a circular orbit perpendicular to a magnetic field of 0.330 T. (a) Compute the radius of the orbit. The answer to this part is 2.07mm. (b) Find the frequency of the motion. I'm not sure …
2. ### Physics

In a certain cyclotron a proton moves in a circle of radius 0.5m. The magnitude of the magnetic field is 1.2T. a) What is the oscillator frequency?
3. ### Physics 3

A 2.3-keV proton is moving horizontally and passes perpendicular to the Earth’s magnetic field at a location where the field magnitude is 52.0 T. i) Determine the magnetic force on the proton?
4. ### Physics 3

A 2.3-keV proton is moving horizontally and passes perpendicular to the Earth’s magnetic field at a location where the field magnitude is 52.0 T. i) Determine the magnetic force on the proton?
5. ### Physics pls help

A proton is moving in a circular orbit of radius 11.8 cm in a uniform magnetic field of magnitude 0.232 T directed perpendicular to the velocity of the proton. Find the orbital speed of the proton. Answer in units of m/s. I came up …
6. ### physics

A proton traveling at 10^4 m/s in the positive x-direction, enters a region where there is uniform electric field of magnitude 10 v/m and a uniform magnetic field of magnitude 10^-2 T. The electric and magnetic fields are parallel …
7. ### physics

A proton traveling at 10^4 m/s in the positive x-direction, enters a region where there is uniform electric field of magnitude 10 v/m and a uniform magnetic field of magnitude 10^-2 T. The electric and magnetic fields are parallel …
8. ### physics-Electric & magnetic fields

A proton traveling at 10^4 m/s in the positive x-direction, enters a region where there is uniform electric field of magnitude 10 v/m and a uniform magnetic field of magnitude 10^-2 T. The electric and magnetic fields are parallel …
9. ### physics

Find the value of the magnetic field necessary to cause a proton moving at a speed of 2.50 ×10^3 m/s to go into a circular orbit of 15.5-cm radius. An electron has an energy of 100 eV as it enters a magnetic field of 3.50 × 10−2 …
10. ### Physics- Final exam review

A proton with kinetic energy 100 keV is moving in a plane perpindicular to a uniform magnetic field of magnitude 2.3 T. Find the radius of its orbit. Not sure what equation to use or how to solve

More Similar Questions

Post a New Question