# algebra2

posted by
**Nancy**
.

If an object is thrown vertically upward with an initial velocity of v, from an original position of s, the height h at any time t is given by: h=-16t^2+vt+s (where h and s are in ft, t is in seconds and v is in ft/sec) Solve for t when the object hits the ground. (when h=0) t=blank 1 Âħsqrt blank 2-4(blank3)/2(-16) fill in the blanks of the quadratic formula. Enter blank 1, blank 2, blank 3