algebra2

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A package with square ends has combined length and girth(girth is perimeter of a cross section) of 120 in. The surface area of the entire package is 3600 sq. in.
Determine the dimensions of the package.
s in. * s in.* l in.
One solution is: 11.08in. * 11.08in. * 75.68in. Find the other solution
Hint: if 4s+length=120 then length=120-4S
Round your answer to 2 decimals. Enter the 3 dimensions separated by commas

• algebra2 -

looks like you defined s to be the measure of each of the sides of the end.
let the length be l
so girth = 4s + l = 120

total area = 2s^2 + 4 sl = 3600
s^2 + 2sl = 1800
s^2 + 2s(120-4s) - 1800 = 0
s^2 + 240s - 8s^2 - 1800=0
7s^2 - 240s +1800 = 0

by the formula
s = (240 ± √7200)/14
s = 11.08 or s = 23.20

if s=23.20 , then l = 120-4(23.20) = 27.18

23.20 , 23.20 , 27.18

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