algebra
posted by Jenna .
(6x2y)/(x^2+xy2y^2)(3x+2y)/(x^2+3xy4y^2)

algebra 
Steve
x^2+xy2y^2 = (x+2y)(xy)
x^2+3xy4y^2 = (x+4y)(xy)
so, the LCD = (x+2y)(x+4y)(xy) and putting it all over that LCD, the numerator then becomes
(6x2y)(x+4y)  (3x+2y)(x+2y)
= 6x^2 +22xy  8y^2
 3x^2 +8xy + 4y^2
= 3x^2 + 14xy  12y^2
so, the final fraction is
3x^2 + 14xy  12y^2

(x+2y)(x+4y)(xy)
Respond to this Question
Similar Questions

bobpursly,
Is this correct now after i revised it Multiply. 3xy^2(5xy4x+6y) 3xy^2(5xy)=15x^2y^3 3xy^2(4x)=12x^2y^2 3xy^2(6y)=18xy^3 so i get from this 15x^2y^312x^2y^2+18xy^3 correct awsome i just thought that the 15x^2y^312x^2y^2 should … 
Algebra
Are these complete? m^2 + 4mn +4n^2 = (m + 2n)(m+2n) 3x^3y^2 – 3x^2y^2 + 3xy^2 = 3xy(x^2y – xy + y) Thank you 
AlgebraPlease check my answers
Posted by Jessie on Monday, October 18, 2010 at 3:48pm. I think I figured it outplease check I'm really stuck on these problems Simplify 6xy(3xy)^2? 
AlgebraPlease check my answers
Posted by Jessie on Monday, October 18, 2010 at 3:48pm. I think I figured it outplease check I'm really stuck on these problems Simplify 6xy(3xy)^2? 
Derive
Find the derivative of sin(2x + 3y)= 3xy + 5y2. I have this so far 1) cos(2x+3y) * d/dx (2x+3y)= 3xy' + 3y + 5y' 2) cos (2x+3y) * [2 + 3y']= 3xy' + 3y + 5y' 3) 3y' cos (2x+3y) + 2cos(2x+3y)= 3xy' + 3y + 5y' 4) 3xy' + 5y'  (3y(cos(3x+3y)= … 
Math help polynomial
multiply the following polynomial 3x(y^2+2y^2) answer choices 3xy^26xy^2' 3xy^2gxy^2 3xy^2+5y^2 9xy^2 The last one was the answer. Can you tell me how the answer was solved? 
algebra 2
(w + 2t)(w^2  2wt + 4t^2) (x + y)(x^2 3xy + 2y^2) =x^3  3x^2y + 2xy^2 + x^2y 3xy^2 + 2y^3 = x^32x^2yxy^2+2y^3 
Simultaneous equation
X+y+z=1......(1) x^2+y^2+z^2=35........(2) x^3+y^3+z^3=97.........(3) solution but from 3 (x^3+y^3)=(x+y)^33xy(x+y)......(4) puting 4 into 3 bck (x+y)^33xy(x+y)+z^3=97.......(5) now from 1 x+y=1z......(6) putin 6 into 7 we have … 
polynomials
I have to simplify (x^5y^4)^4(3x^2y)^2(1/3xy) I did (x^20y^16)(9x^4y^2)(1/3xy) (9x^24y^18)(1/3xy) 3x^25y^19 Is this correct? 
Pre Algebra
Simplify: 1: (12xy2z)(3xy) 2: 12xy2z divided by 3xy 3: 2x(2x  5) 4: 2x(2x5) Please help!