Calculate the pressure drop expected on hydrogenation of the mixture of 5.00 ml of cyclohexene and 35 ml of cylclohexane. I know I have to use PV=nRT but this is all I know we are starting at 60 psi of pressure. We also used hydrogen gas if that helps
To calculate the pressure drop expected during the hydrogenation of the mixture, we will need some additional information. Specifically, we need to know the volume of the hydrogen gas used and the conditions under which the reaction takes place.
However, let's assume that the hydrogenation reaction takes place at constant temperature and in an ideal gas state. In this case, we can use the ideal gas law equation, PV = nRT, to calculate the pressure drop.
Given:
Initial pressure (Pi) = 60 psi
Volume of cyclohexene (V1) = 5.00 ml
Volume of cyclohexane (V2) = 35 ml
Since we are assuming the reaction is taking place at constant temperature, we can also assume that the moles of hydrogen gas (n) remain constant throughout the reaction.
We can rewrite the ideal gas law equation as:
(P1 * V1) + (P2 * V2) = nRT
Since we are interested in the pressure drop (ΔP), we can rearrange the equation to solve for the change in pressure:
ΔP = P2 - P1 = (nRT - (P1 * V1)) / V2
Now, the missing piece of information is the volume of hydrogen gas used (VH2). If you have this information, you can substitute it into the equation. Once you know that value, you can proceed with the calculation.