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A force F=Fx ˆi + Fy ˆj + Fz ˆk acts on a particle located at X= (x, y, z). Given Fx=−88.3N, Fy=7.56N, Fz=60N, x= −3.65m, y=1.67m and z=7.03m,
calculate the three components of the torque vector ~ = xˆi + y ˆj + z ˆk .
First, calculate the x component.

M = R cross F

i j k
x y z
Fx Fy Fz determinant

=(y Fz-z Fy)i+(z Fx-x Fz)j *(x Fy-y Fx)k

so x component
(y Fz-z Fy)
= 1.67*60 - 7.03*7.56
= 47.1 Nm

How do you calculate the y component.
How do you calculate the z component.

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