trigonometry
posted by lindsay .
Hal walked from point A to point B due north east from a distance of 20m. He immediately changed direction and walked 50m from B to C on a bearing of 110 degrees.
1. calculate the distance AC
2. Find the bearing of C from A

I made a sketch and got a triangle ABC where AB = 20
BC = 50 and angle B = 70°
by the cosine law:
AC^2 = 20^2+50^22(20)(50)cos70
= 2215.959...
AB =47.07 m
Using the sine law, find angle A