Chemistry
posted by Hannah .
.50  x / x = 3.20e1
I need to solve for x. I was going to do .50 X 3.20e1 and then take the square root but this is not correct. I am not sure what to do. Thank you for your help.
Math(Please help)  Reiny, Tuesday, April 17, 2012 at 3:18pm
You probably meant
(.50  x)/x = 3.2 e^1= 3.2/e
crossmultiply ...
.50  x = (3.2/e)x
(3.2/e)x + x = .5
x(3.2/e + 1)
x = .5/(3.2/e + 1)
multiply by e/e
= .5e/(3.2 + e)
multiply by 10/10
= 5e/(32 + 10e)
So I have to multiply 5e by 10 which would be 50e and then multiply (32+10e) by 10?
Math(Please respond)  bobpursley, Wednesday, April 18, 2012 at 7:17pm
Hannah: Professor Reiny solved it for you.
x= 10e/(32+10e)
calculate that. Or if you cant, put this in your google search window
10*e/(32+10*e) =
I understand. If the number was 2.49e1 I would do the same thing, so it would be 10*e / (249 + 10*e) = ?. Is this correct?

I started to write this a couple of days ago when I saw this post but didn't. Frankly, I thought both professor Reiny and professor Pursley misinterpreted the question. I still think so. I don't think it has anything to do with e. I believe you meant
[(0.50x)/x] = 3.20E1 which I would rewrite as
0.320 = (0.50x)/x, then
0.320x = 0.50x
1.320x = 0.50 and
x = 0.50/1.320
x = ? 
Ok thank you the way you have it is exactly the way that it was stated on my homework. The only problem is that I realized that I had the typed the wrong number. It was suppose to be the same equation but with 2.49e1 instead 3.20e1. I understand everything except how did you get 1.320?

0.320 = (0.50x)/x, then
0.320x = 0.50x
0.320x = 0.50 x
add x to both sides.
0.320x + x = 0.50 x +x
0.320x + 1x = 0.50
1.320x = 0.50 and
x = 0.50/1.320.
1.320x = 0.50 and
x = 0.50/1.320 
Thank you.
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