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A particle has a de Broglie wavelength of 3.30 10-10 m. Then its kinetic energy quadruples. What is the particle's new de Broglie wavelength, assuming that relativistic effects can be ignored?

  • physics -

    λ =h/p,
    KE = p^2/2•m
    p =sqrt(2•m•KE)
    λ1 =h/sqrt(2•m•KE1),
    λ2 =h/sqrt(2•m•KE2)=
    = h/sqrt(2•m•4•KE1)=
    = h/sqrt(4•p)= λ1/2 =
    =1.65•10^-10 m.

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