posted by Anonymous .
The chemical reaction N2(g) + 3 H2(g) ↔ 2 NH3(g) is at equilibrium. An experimenter injects a small amount of N2 into the reaction chamber. What happens to the forward reaction rate right after the injection of the N2?What happens to the reverse reaction rate right after the injection of the N2? What happens to the forward reaction rate after the injection of the N2 until equilibrium is re-established? What happens to the reverse reaction rate after the after the injection of the N2until equilibrium is re-established? When equilibrium is established, what is the relationship between the forward and the reverse reaction rate?
When N2 is injected the forward reaction increases because N2 is larger. The reverse direction also increases since products are forming at a greater rate. At the end when equilibrium is re-established the forward reaction rate = reverse reaction rate.