posted by John .
A cube of ice is taken from the freezer at -8.8°C and placed in a 103 g aluminum calorimeter filled with 321 g of water at room temperature of 20°C. The final situation is observed to be all water at 15°C. What was the mass of the ice cube?
Could someone please help me get a setup to solve for this problem with indicating what is what please. Thank you.
m2 = 0.321 kg,
m3 = 0.103 kg,
c1 = 2060 J/kg•degr is heat capacity of ice,
c2 = 4180 J/kg•degr is heat capacity of water,
c3 = 930 J/kg•degr is heat capacity of Al,
r =335000 the heat of fusion (ice-water),
Δt1 = 8.8 degr, Δt2 = 15 degr, Δt3 = 5 degr.
m1• c1• Δt1 + r• m1 + m1• c2• Δt2 = c2• m2•Δt3 +c3• m3• Δt3,
m1 = Δt3•( c2• m2 +c3• m3 )/( c1• Δt1 + r + c2• Δt2)
Thanks Elena your a life saver :)