PHYSICS

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An electron is located on a pinpoint having a diameter of 2.04 µm. What is the minimum uncertainty in the speed of the electron?

  • PHYSICS -

    Δx• Δp ≥ ħ / 2
    Δx •m •Δv ≥ ħ / 2
    Δv ≥ ħ / 2• m •Δx
    The minimum uncertainty in speed
    Δv = ħ / 2• m •Δx =
    =( h / 2 π ) / 2• m •Δx =
    = h / 4• π •m •Δx .
    Using the diameter of the pinpoint for the uncertainty in position
    Δv =6.63•10^-34/4•π•9.1•10^-31•2.04•10 ^-6 =
    = 28.37 m/s.

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