intermediate algebra
posted by Lueshelle .
Factor the expression 64a^216ab+b^2 into a product of binomials

Use the AC method.
A*C = 64(1) = (8)(8).
64a^2 + (8ab8ab) + b^3 =
Arrange the 4 terms to form 2 factorable pairs:
(64a^28ab)) + (8ab+b^2) =
8a(8a+b) + b(8a+b) =
(8a+b)(8a+b).
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