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find an equation for the hyperbola vertices (3,0),(3,4) asymptotes:y=2/3,y=4-2/3x

  • pre-cal -

    center midway between vertices at (3,2)
    slope of asymptote 2/3 = a/b

    (y-2)^2/4 - (x-3)^2/9 = 1

  • pre-cal -

    thank you very much

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