Chemistry

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A 1.00-L solution saturated at 25°C with calcium oxalate (CaC2O4) contains 0.0061 g of CaC2O4. The solubility constant (Ksp) for this salt is [CaC2O4=128.09 g/mol]

  • Chemistry -

    0.0061g/128.09 = 4.76E-5
    .........CaC2O4 ==> Ca^2+ + C2O4^2-
    equil....4.76E-5..4.76E-5...4.76E-5

    Ksp = (Ca^2+)(C2O4^2-)
    Substitute from the ICE chart and solve for Ka.

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