Algebra
posted by Nikki .
Solve for x: (x/4)(5/x)=(1/4)

how about multiplying each term by 4x ?
x^2  20 = x
x^2  x  20 = 0
solve for,
an easy one, it factors 
Wouldn't it be x^220=4 since (1/4)•4x= (4x/4)? So that means it would be x^224=0, right? Where would I go from there?

...since (1/4)•4x= (4x/4)?
yup, and what is 4x/4 ?
isn't that x ?
so you know how to factor simple trinomials?
x^2  x  20 = 0
(x5)(x+4) = 0
so x = 5 or x = 5
check:
if x = 5
5/4  5/5 = 5/4  1 = 1/4 , check!
if x = 4
4/4  5/4
= 1 + 5/4 = 1/4 , check!
my answers are correct 
Ay, my bad. Thanks :) and you mean x=5 or x=4 right?

right, x = 5 and x = 4,
my bad, lol 
Haha its ok. Thanks for the help.