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C3H8+5O2=3CO2+H2O How many liters of propaine (d=0.585g/ml) will produce 1.25L of water (d=1.00g/mL)?


    First you balance the equation.
    C3H8 + 5O2 ==> 3CO2 + 4H2O
    1.25L H2O with density 1.00 g/mL = 1,250 grams.
    mols H2O = grams/molar mass = ?
    Convert to mols C3H8 using the coefficients in the balanced equation.
    ?mol H2O x (1 mol C3H8/4 mols H2O) = xx mol C3H8. Then g = mols C3H8 x molar mass. Convert to mL using the density.

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