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find the slope of the tangent line at the point (1,2) for the ellipse 2x^2+3y^2=14

y'(1) = ??

  • calculus -

    differentiate implicitly

    4x + 6y dy/dx = 0
    dy/dx = -6y/(4x) = -3y/(2x)

    sub in (1,2) to get the slope

    take it from there

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