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a bullet is fired from the ground at the angle of 30 degree above the horizontal,What initial speed must the bullet have in order to hit a point 250 ft high on a tower located 400 ft away (ignoring air resistance),what the solution?

  • physic -

    Write vertical and horizontal equations of motion. Require that X = 400 and Y = 250 at same time, t. You have two equations for the two unknowns, t and Vo. They are:

    X = Vo*cos30 * t = 400
    Y = Vo*sin30 * t - (g/2) t^2 = 250

    I recommend using the X equation to substitute for t in the second (Y) equation.

    g = 32.2 ft/s^2.

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